7x^2-37x+48=0

Solution for 7x^2-37x+48=0 equation:

7x^2-37x+48=0

a = 7; b = -37; c = +48;
Δ = b2-4ac
Δ = -372-4·7·48
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-5}{2*7}=\frac{32}{14}
=2+2/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+5}{2*7}=\frac{42}{14}
=3
$